This post is all about the solution of the "C. Minimize the Thickness" Codeforces Round #826 (Div. 3) Problem Statement.
Problem Statement :
You have been given this same sequential b=[b1,b2,...,bn] of m positive integers.
A segment is a group of consecutive elements. Each segment has two indices: the indicator at its left end and the index at its right end. A segment of the series a with the left end in l as well as the right end in r is denoted by a[l,r].
We segmented the given sequence a so that every element is in precisely one segment and the sums of elements in all sections are equivalent.
Each element corresponds to a particular segment, as well as the total of the elements in each segment is 100.
Let us define divided thickness as the duration of the longest segment. For instance, consider the width of the split in the instance.
Discover the slimmest possible divide of a sequence of an into sections in the expected performance.
Format of Input :
The first line contains a single integer t (1<=z<=100), which represents the number of test cases.
Lines describe evey test scenarios.
Evey test case starts with a single integer m (1<=m<=2000) — the length of the sequential b.
Evey test case's second sentence actually contains m integers: b1,b2,...,bm (1<=bi<=106) — elements of the sequential b.
The sum of m for all tests is assured not to surpass 2000.
Format of the Output :
Output each numeric value for every test case indicating the smallest potential depth of a segmented split of the sequential b.
Bear in mind that there is constantly a split; you always can think of the entire series to be one section.
Also Check this out:-
A. Compare T-Shirt Sizes Codeforces Round #826 (Div. 3) Problem Solution Click Here
B. Funny Permutation Codeforces Round #826 (Div. 3) Problem Solution Click Here
C. Minimize the Thickness Codeforces Round #826 (Div. 3) Problem Solution Click Here
D. Masha and a Beautiful Tree Codeforces Round #826 (Div. 3) Problem Solution Click Here
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